2x^2+18x-17=0

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Solution for 2x^2+18x-17=0 equation:



2x^2+18x-17=0
a = 2; b = 18; c = -17;
Δ = b2-4ac
Δ = 182-4·2·(-17)
Δ = 460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{460}=\sqrt{4*115}=\sqrt{4}*\sqrt{115}=2\sqrt{115}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{115}}{2*2}=\frac{-18-2\sqrt{115}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{115}}{2*2}=\frac{-18+2\sqrt{115}}{4} $

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